# What are effects on academia now that ChatGPT has made homework pointless?

1. 6 months ago
Anonymous

Not as big as the effects it will have on systemd

• 6 months ago
Anonymous

not seen any instance of chatgpt replacing anything. you'd have to be a severely crippled moron to believe it has had any impact on anything except allowing people to generate somewhat coherent fucking gibberish like this:

if you submitted this shit as homework you'd be laughed out your school.

• 6 months ago
Anonymous

Listen up, buddy. AI is the future and you'd better get used to it. Today's students have grown up with technology, and AI is the next step. It can handle a huge range of tasks, from simple calculations to complex analysis. And let's face it, homework isn't exactly the most stimulating activity for kids. So why not use AI to do the mundane tasks, freeing up time for students to actually learn and explore? AI can be programmed to do it faster, better and more accurately than any human can. So yeah, the days of doing repetitive, mind-numbing homework are over. Get with the times!

• 6 months ago
Anonymous

Because most students don’t learn at all? Most are retarded braindead gays that contribute nothing to our society

And reading up recent news, I prefer them crying over basic algebra, rather than doing stupid shit for likes on the internet

You’re being an idealist if you think kids are going to “learn”, complex analysis? Algebra? Programming? Nah, now that cool AI can do homework they will watch Fornite porn

The future of humanity for sure!

• 6 months ago
Anonymous

I challenge you to give me a (reasonable) homework problem for chatgpt to answer, if you don't think it can do it.

• 6 months ago
Anonymous

Very easy:
if x^2 + 3x - 2 = 0, then what is the largest possible value of x?
Easy:
say that (a+b) = 7 and (a-b) = 5. what is a^2 - b^2?
Medium:
Find the distance from the point (1, 2, 3) to the line parametrized by p(t) = (3, 2, 1) + t(4, 5, 6)
Hard:
integrate the indefinite integral int(x^4 + sin(x)cos(x) dx)

• 6 months ago
Anonymous

I'm not gonna figure out how to enter mathematical notation into the textbox so I'm skipping these

• 6 months ago
Anonymous

Don’t bother converting it to mathematical notation. Just paste it in. The AI should be able to handle it

• 6 months ago
Anonymous

The integral doesn’t even need AI anon, just use Symbolab

• 6 months ago
Anonymous

This is shit wolframalpha could do 10 years ago

This is shit mathematica could do 30 years ago.

https://i.imgur.com/LrRh6LU.png

[...]
Didn't even need AI. I used this for calc homework (before you had to pay to see the work)

That’s the point. I want to see how well the AI stacks up against software we already have. Honestly I think the AI will do worse since it’s not designed to correctly answer math problems

• 6 months ago
Anonymous

This is shit wolframalpha could do 10 years ago

• 6 months ago
Anonymous

This is shit mathematica could do 30 years ago.

• 6 months ago
Anonymous

Hard:

To integrate this integral, we can use the following property of integration:

int f(x)g(x) dx = F(x)G(x) + int F(x)g'(x) dx

where F(x) and G(x) are the antiderivatives of f(x) and g(x), respectively.

In this case, we have f(x) = x^4 and g(x) = sin(x)cos(x). Therefore, the antiderivatives of f(x) and g(x) are F(x) = x^5/5 and G(x) = -sin^2(x)/2.

Substituting these antiderivatives into the property of integration above, we get:

int(x^4 + sin(x)cos(x)) dx = (x^5/5) (-sin^2(x)/2) + int (x^5/5) (-cos^2(x)) dx

To evaluate the last integral, we can use the identity cos^2(x) = 1 - sin^2(x) to write it as:

int (x^5/5) (-cos^2(x)) dx = int (x^5/5) (-(1 - sin^2(x*~~ dx

Using the property of integration again, we have:

int (x^5/5) (-(1 - sin^2(x*~~ dx = (x^5/5) (-x + sin^3(x)/3) + int (x^6/30) (-3sin(x)) dx

To evaluate the last integral, we can use the identity sin^3(x) = (3sin(x) - 4sin^3(x))/4 to write it as:

int (x^6/30) (-3sin(x)) dx = int (x^6/30) (-(3sin(x) - 4sin^3(x))/4) dx

Using the property of integration again, we have:

int (x^6/30) (-(3sin(x) - 4sin^3(x))/4) dx = (x^6/30) (-3x/4 + sin^4(x)/8) + int (x^7/210) (-4sin^2(x)) dx

To evaluate the last integral, we can use the identity sin^4(x) = (1 - 2sin^2(x) + sin^4(x))/2 to write it as:

int (x^7/210) (-4sin^2(x)) dx = int (x^7/210) (-(1 - 2sin^2(x) + sin^4(x))/2) dx

Using the property of integration again, we have:

int (x^7/210) (-(1 - 2sin^2(x) + sin^4(x))/2) dx = (x^7/210) (-x/2 + sin^2(x) - sin^6(x)/6)

Therefore, the indefinite integral of int(x^4 + sin(x)cos(x)) dx is:

(x^5/5) (-sin^2(x)/2) + (x^5/5) (-x + sin^3

I think it got cut off since it was using up so much space explaining its work

• 6 months ago
Anonymous

>I think it got cut off since it was using up so much space explaining its work
it's wrong - you first use the linearity of the integral and then integration by parts, where (sin x)' = cos x, so you just have to deal with one function. The AI misunderstood the question.

• 6 months ago
Anonymous

Hard:

To integrate this integral, we can use the following property of integration:

int f(x)g(x) dx = F(x)G(x) + int F(x)g'(x) dx

where F(x) and G(x) are the antiderivatives of f(x) and g(x), respectively.

In this case, we have f(x) = x^4 and g(x) = sin(x)cos(x). Therefore, the antiderivatives of f(x) and g(x) are F(x) = x^5/5 and G(x) = -sin^2(x)/2.

Substituting these antiderivatives into the property of integration above, we get:

int(x^4 + sin(x)cos(x)) dx = (x^5/5) (-sin^2(x)/2) + int (x^5/5) (-cos^2(x)) dx

To evaluate the last integral, we can use the identity cos^2(x) = 1 - sin^2(x) to write it as:

int (x^5/5) (-cos^2(x)) dx = int (x^5/5) (-(1 - sin^2(x*~~ dx

Using the property of integration again, we have:

int (x^5/5) (-(1 - sin^2(x*~~ dx = (x^5/5) (-x + sin^3(x)/3) + int (x^6/30) (-3sin(x)) dx

To evaluate the last integral, we can use the identity sin^3(x) = (3sin(x) - 4sin^3(x))/4 to write it as:

int (x^6/30) (-3sin(x)) dx = int (x^6/30) (-(3sin(x) - 4sin^3(x))/4) dx

Using the property of integration again, we have:

int (x^6/30) (-(3sin(x) - 4sin^3(x))/4) dx = (x^6/30) (-3x/4 + sin^4(x)/8) + int (x^7/210) (-4sin^2(x)) dx

To evaluate the last integral, we can use the identity sin^4(x) = (1 - 2sin^2(x) + sin^4(x))/2 to write it as:

int (x^7/210) (-4sin^2(x)) dx = int (x^7/210) (-(1 - 2sin^2(x) + sin^4(x))/2) dx

Using the property of integration again, we have:

int (x^7/210) (-(1 - 2sin^2(x) + sin^4(x))/2) dx = (x^7/210) (-x/2 + sin^2(x) - sin^6(x)/6)

Therefore, the indefinite integral of int(x^4 + sin(x)cos(x)) dx is:

(x^5/5) (-sin^2(x)/2) + (x^5/5) (-x + sin^3

I think it got cut off since it was using up so much space explaining its work

Didn't even need AI. I used this for calc homework (before you had to pay to see the work)

• 6 months ago
Anonymous

Technically it IS AI, it just isn't DL (or even ML).

• 6 months ago
Anonymous

I'm intrigued. Have a text book from undergrad where I remember the problems were particularly difficult to google. Don't remember specific problems but here's a couple of varying difficult.

1. Find blood flow through a vein with a circular cross section. The vein has a diameter of 0.5 cm and is 15 cm long. Blood has a density of 105 g/ml and a viscosity of 5 cp. The inlet pressure is 5cmH2O greater than the outlet pressure.

2. Derive expressions for the velocity profile and flow rate of a power law fluid the flows through a cylindrical tube of length L and radius R.

3. (No way in hell it gets this one) Ethylene glycol is used as an antifreeze in automobiles. This is a sweet compound and spilled ethylene glycol is unknowingly ingested by dogs and other animals. By itself, this compound is not harmful to the body and is readily excreted in the urine. However, once ingested, ethylene glycol is converted by the enzyme alcohol dehydrogenase to an aldehyde, which in turn is converted into a toxin. Use your knowledge of enzyme kinetics to search for an inhibitor of alcohol dehydrogenase and to find an appropriate dose that can minimize the conversion of ethylene glycol to aldehydes.

• 6 months ago
Anonymous

Question 1:

To find the blood flow through a vein with a circular cross section, you will need to use the Hagen–Poiseuille equation. This equation relates the flow rate of a fluid through a long, straight tube with circular cross section to the pressure difference between the ends of the tube, the viscosity of the fluid, and the length and radius of the tube.

The Hagen–Poiseuille equation is given by:

Q = (π * r^4 * (P1 - P2)) / (8 * η * L)

where Q is the flow rate, r is the radius of the tube, P1 and P2 are the pressures at the inlet and outlet of the tube, η is the viscosity of the fluid, and L is the length of the tube.

In your case, the radius of the tube (r) is 0.25 cm (since the diameter of the vein is 0.5 cm), the length of the tube (L) is 15 cm, the viscosity of the blood (η) is 5 cp, and the pressure difference between the inlet and outlet of the tube (P1 - P2) is 5 cmH2O. Plugging these values into the Hagen-Poiseuille equation, we get:

Q = (π * 0.25^4 * 5) / (8 * 5 * 15)

Q = 0.001723 cubic centimeters per second

This is the flow rate of the blood through the vein with a circular cross section. The density of the blood does not affect the flow rate in this calculation, as it cancels out when the viscosity and the flow rate are calculated.

• 6 months ago
Anonymous

I did question 3
>Ethylene glycol is converted to aldehyde by the enzyme alcohol dehydrogenase (ADH). Inhibition of ADH can prevent the conversion of ethylene glycol to aldehyde and minimize its toxicity. There are several potential inhibitors of ADH that can be used to prevent this conversion. One example is fomepizole, which is a specific inhibitor of ADH and is commonly used as an antifreeze antidote. Fomepizole is generally administered in a dose of 15 mg/kg, given intravenously over a period of 30 minutes. This dose can effectively inhibit ADH and prevent the conversion of ethylene glycol to aldehyde.

• 6 months ago
Anonymous

Looking at the answer to this it no longer seems as hard as the question made it sound. Guess it was literally googling for an alcohol dehydrogenase inhibitor. The other two though, honestly pretty impressed. Nobody in college is going to learn anything.

• 6 months ago
Anonymous

... maybe that's a boon then. My position is definitely going to be secure.

• 6 months ago
Anonymous

Because most students don’t learn at all? Most are retarded braindead gays that contribute nothing to our society

And reading up recent news, I prefer them crying over basic algebra, rather than doing stupid shit for likes on the internet

You’re being an idealist if you think kids are going to “learn”, complex analysis? Algebra? Programming? Nah, now that cool AI can do homework they will watch Fornite porn

The future of humanity for sure!

Only hope for academia is to put more emphasis on testing, while being monitored and probably without tech involved

• 6 months ago
Anonymous

Which means online courses have to go the way of the dodo

• 6 months ago
Anonymous

nope. you can still do oral examinations and large projects, but of course that requires the professors to give a fuck about their students which would never happen

• 6 months ago
Anonymous

What is with retards not wanting to use tech?
In the real world, you have to figure out how to use a computer to get your intended result as quickly as possible. Anything else is mental masturbation.
>but you don't truely learn it
moron go look at the American mathematical monthly, it's crazy all the stuff they did that is just useless now, imagine spending your time learning to graph by hand, when we have REAL PROBLEMS that don't involve graphing and when graphing and drawing is a solved problem.

• 6 months ago
Anonymous

https://i.imgur.com/9g6Zqyz.png

nope. you can still do oral examinations and large projects, but of course that requires the professors to give a fuck about their students which would never happen

"teaching" and academia are two different things. The fundamental organization of those things was always retarded (profs' duty, what they're promoted based on, how they're paid, and what they want to do is research, not teaching. Teaching is just something they're forced to do for the privilege). Hence why they'll never care about teaching, and also why this will end in disaster.
The real solution is obvious: it's not more tests (which will be cheated on as always), it's more practicum. In fact, get rid of undergrad, just have people train in a career path since young by working as early as 8 or so.

• 6 months ago
Anonymous

>Only hope for academia is to put more emphasis on testing, while being monitored and probably without tech involved
ah yes, what we really need are neo-luddites who can do nothing but regurgitate facts like robots. clearly it is china and india (who largely do that in high ed) are the leading technological marvels, not enormous sweatshops with a few high-tech silos ripped off from the west.

• 6 months ago
Anonymous

Question 2:

The velocity profile of a power law fluid flowing through a cylindrical tube can be derived from the Hagen-Poiseuille equation, which states that the velocity of the fluid at any point within the tube is given by:

\$\$v(r) = frac{Q}{pi R^4} cdot frac{1}{n} cdot left( R^2 - r^2 right)\$\$

where \$Q\$ is the volumetric flow rate, \$R\$ is the radius of the tube, \$n\$ is the power law index of the fluid, and \$r\$ is the distance from the center of the tube.

The volumetric flow rate of the fluid can be calculated using the equation:

\$\$Q = int_0^R v(r) cdot 2 pi r , dr\$\$

Substituting the expression for \$v(r)\$ into this equation, we get:

\$\$Q = frac{2}{n} int_0^R frac{Q}{pi R^4} cdot left( R^2 - r^2 right) cdot r , dr\$\$

Evaluating this integral, we find that the volumetric flow rate is given by:

\$\$Q = frac{Q}{n} cdot frac{pi}{4} cdot R^2\$\$

Thus, the expression for the velocity profile of a power law fluid flowing through a cylindrical tube of radius \$R\$ and length \$L\$ is given by:

\$\$v(r) = frac{Q}{pi R^4} cdot frac{1}{n} cdot left( R^2 - r^2 right)\$\$

and the expression for the volumetric flow rate is given by:

\$\$Q = frac{Q}{n} cdot frac{pi}{4} cdot R^2\$\$

These expressions can be used to calculate the velocity profile and flow rate of a power law fluid flowing through a cylindrical tube of given dimensions and properties.

• 6 months ago
Anonymous

It generates content organized into an essay written in a manner that you specify. You can always run it through a plagiarism checker and proper spin bot if you really feel the need. The question is what is it even specifically plagiarising? You need some sort of proof. Worst case scenario you edit it in your grammatical style and language but the brunt of the work is done you and a great deal of time is saved. Don't tell me you elitists aren't smart enough to do that while the Chinese cheat more than they brush tbeir teeth.

>if you submitted this shit as homework you'd be laughed out your school.
Yes anon. The AI tsundere ranting about Lennart and calling him a baka, as it was requested to do, is clearly meant to be a homework submission and it riles you up. Thank you for letting us know about your autism disability.

• 6 months ago
Anonymous

The average schizo has a better grasp on conceptualization than GPT. With enough monkeys you can write Shakespeare, the same could already be said for pajeets in Homework Help services.

2. 6 months ago
Anonymous

It will close the black/white achievement gap, because now there's nothing special about a genius tier Aryan galaxy brain even when compared to a sub-Saharan.

3. 6 months ago
Anonymous

seems to not apply to math majors

• 6 months ago
Anonymous

Math majors believe what you're showing is not math.
They believe only useless things (but mostly in the proof kind of area) is real math.
Incidentally, gpt is great at spamming proofs.

• 6 months ago
Anonymous

it has a very... interesting view of mathematics

• 6 months ago
Anonymous

That's hilarious.
What if you phrase it more like a direct statement?
>Does there exist a differentiable function f : R R such that f ′ (0) = 0
but f ′ (x) ≥ 1 for all x 6= 0?
>Suppose fn : A R is uniformly continuous on A for every n ∈ N
and fn f uniformly on A. Prove that f is uniformly continuous on A.

• 6 months ago
Anonymous

>mfw in the when 7625597484987 overflows to a negative number it becomes less than 27

• 6 months ago
Anonymous

yeah you'll be coping and seething when your newfangled x^x^x overflows bigint while x^x will be steadily chugging along

• 6 months ago
Anonymous

Chatbots really do struggle to stay on topic, huh?

• 6 months ago
Anonymous

got one step right but it is wrogn:
x = 0.8888...
10x = 8.8888...
10x - x = 9x = 8
x = 8/9